N O V I T A !!!!!
Vi posto l'ultimo messaggio preso del forum di MEG_Builder di Yahoo dove Carbonprobe e' riuscito a far funzionare il Magnete !!!!!
I reported to this group many months ago that I saw a change in
output voltage when I pulled the magnet in my Meg. But I wasn't able
to repeat it, so I thought it was just a mistake and just went on
thinking nothing of it. Well, I'm seeing the anomaly again, so it's
definately repeatable.
Joe Flynn who has a patent (US6246561) similar to the meg says that
in order to switch the magnet's flux in the core, your input coil's
Voltage and current need to be close to 90 degrees out of phase. So I
tested this out, and sure enough, he was right.
My set up is this: I'm only using the Left input coil as an input and
leaving both secondaries open. When the magnet is inserted, the input
current increases 6.8%, the left output coil voltage increases 10%,
and the right output coil voltage increases 28.3%. I've included all
my measurememts below.
If I do a frequency sweep, around 25kHz I leads V by 90 degrees and
output is small. Around 36khz V and I are in phase and the output
voltage is the largest (resonance 1). Around 47KHz V leads I by 90
degrees and output goes down a little. Then around 54Khz V and I are
in phase and output goes up again somewhat (resonance 2). Around
60KHz V leads I again by ~90 degrees and output goes down. As I go
higher in frequency the phasing gets closer to 90 degrees and input
current draw goes way up, almost fried my Mosfet. At 57Khz I got the
smallest current draw, so there is where I took my measurements.
InVDC = input DC voltage
InIDC = input DC current in Amps
VLpp = Left output coil peak to peak voltage
VRpp = Right output coil peak to peak voltage
M = means measurement taken with magnet inserted
N = means measurement taken with no magnet
InVDC InIDC VLpp VRpp
25 0.102 1700 330 N
25 0.111 1900 460 M
25 0.103 1700 320 N
25 0.110 1850 430 M
25 0.1035 1710 330 N
25 0.111 1900 460 M
The output and current draw went down when I tried a weaker magnet.
the spaceing between my cores is 0.5mm. The input coils are 100 turns
each and the ouput coils are 800 turns each. Input was a 50% duty
cycle square wave, output coils were sine waves. At lower frequencies
the magnet actually causes the output voltage to decrease when you
insert it.
To me, this is proof of flux switching. And now the main objective is
to optimize this effect to get the largest unloaded output voltage
possible. This is where the fine tuning comes in. If someone else
could replicate this I think it would be an important turning point.
Steve Sullivan has kindly disclosed that the trick to get the Meg to
work is when the input is on, don't apply a load. When the input is
turned off, apply the load. And load the meg to get optimum output
just like you would a speaker system to get optimum output,
conditioned resistors aren't necessary.
As I reread my old EE books I discover more things about the meg. In
a normal transformer the output coil couples with the input coil via
the magnetic circuit in the core. The back EMF causes the input
current to go up. If you can find a way to not couple the input coil
with the output coil in the same magnetic path, then back emf won't
cause the input current to be so high. In the Meg applying the load
after the input is turned off will achieve this. As the magnet decays
to it's steady state the changing B field creates a voltage, and this
is where you can extract energy.
I think it's also possible to load the meg in a way that when the
left input coil is on, the left output coil should be unloaded and
the right output coil loaded. When you pulse the left input coil to
oppose the magnet's field in that side, the permeability (u=B/H)
becomes very small, B is close to zero on the left side, making u
very small like an air gap, thus making the Reluctance very large. On
the right side where all the magnet's B field is forced, you have a
large B value, making u larger than the left side, and thus making
reluctance smaller than the left side. So if you apply a load to the
right side, the back EMF won't be reflected back to the left input
coil because of the difference in reluctance and permeability.
And so the right output coil doesn't share a common magnetic path
with the left input coil. But the left output coil does share a
common magnetic path with the left input coil, so you wouldn't want
to load it because it would cause back emf to affect the left input
coil. I've done calculations on this and I am still working on it,
I'll post them soon.
Ken
Vedremo di immitarlo !!!!!!!
Ciao a tutti
ppure si puo' variare la frequenza di lavoro ma in questo caso non si riescono ad avere caratteristiche identiche alla stessa frequenza.